VFP 愛用者社區

[jtcom01]

請教各位先進..如標題..
但..我在程式的最後面加上一行 READ TIME 0.01
就不會出現上述的訊息..為什麼呢?這樣是否解決了堆疊錯誤的問題呢?
請教各為先進..無限感激..

[saint]

有..read time 這一個指令?

[jtcom01]

read time 是搜尋c0000005問題時..有位先進使用的方法..確實能避開堆疊問題..

[syntech]

Activates objects created with @ ... GET and @ ... EDIT commands.

Syntax

READ
[CYCLE]
[ACTIVATE <expL1>]
[DEACTIVATE <expL2>]
[MODAL]
[WITH <window title list>]
[SHOW <expL3>]
[VALID <expL4 | expN1>]
[WHEN <expL5>]
[OBJECT <expN2>]
[TIMEOUT <expN3>]
[SAVE]
[NOMOUSE]
[LOCK | NOLOCK]
[COLOR <color pair list> | COLOR SCHEME <expN4>]

Remarks

READ activates objects. Objects are GET fields, check boxes, lists, popups, push buttons, radio buttons, spinners and text editing regions defined with @ ... GETs. READ activates all objects created after the last READ or CLEAR GETS was issued.

TIMEOUT <expN3>

A TIMEOUT clause determines how long the READ is in effect. <expN3> specifies the number of seconds that can elapse without user input before the READ is terminated. If the READ is terminated by a TIMEOUT clause, READKEY(? returns 20 if changes have not been made to any object. If changes have been made, READKEY(? returns 276.
When READ is terminated by a TIMEOUT clause, any changes made to the field being edited when the READ ends are discarded. However, changes made to other fields are saved.

[syntech]

實際上這是一個古早的語法.
上面的敘述是由 FPW 2.6 的 HELP 中節錄出來的.

READ TIME 0.01 = READ TIMEOUT 0.01

也就是作一個假的讀取,讓系統有一個 0.01 秒的空檔.

因為 C000005 通常是 記憶體非法存取 的錯誤(memory access violation),
FOXPRO 的命令基本上笨到不知道做完了沒就繼續下去,
這個 0.01 秒的空檔能讓 FOXPRO 的背景執行緒完成應該完成的工作,
可能藉此閃躲 C000005 的錯誤.
不表示這個命令有什麼神奇的功效.

我猜用在這個地方也是如此.

[jtcom01]

謝謝SYNTECH先進..不吝指導..
SET STEP ON 執行到 READ EVEN 指令時..出現堆疊不正常..這樣算正常嗎?

[syntech]

不正常.

不正常也沒用,因為你不是用"正確"的指令作事.

[jtcom01]

請教..syntech先進..是否可以更明確的指正呢?
程式下..
SET STEP ON
DO XXX.MPR
READ EVENTS
執行到..READ EVENTS 時..出現
(呼叫堆疊不正確:中斷間的追蹤已關閉)

[jtcom01]

請教..syntech先進..是否可以更明確的指正呢?
程式下..
SET STEP ON
DO XXX.MPR
READ EVENTS
執行到..READ EVENTS 時..出現
(呼叫堆疊不正確:中斷點之間的追蹤已關閉)